-x-10/x^2+x-2

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Solution for -x-10/x^2+x-2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x-x-(10/(x^2))-2 = 0

x-x-10*x^-2-2 = 0

-10*x^-2 = 2 // : -10

x^-2 = -1/5

-2 < 0

1/(x^2) = -1/5 // * x^2

1 = -1/5*x^2 // : -1/5

-5 = x^2

x belongs to the empty set

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